Optional Chaining and Type Narrowing

[arciisine]

Search Terms

Optional Chaining

Suggestion

Currently I use a pattern of an in check with a ternary to narrow type on optional fields. With the new optional chaining, it would be great if the type narrowing could occur as the optional chain is progressed.

Use Cases

The primary use here is for type narrowing on union types without the need for extra boilerplate.

Examples

Current method of using the in operator for type narrowing.

type Header = { headers: Record<string, any> };
type Options = { config : any };

function getHeader(input: Header | Options, key: string, def?: any) {
   return ('headers' in input ? input.headers[key] : undefined) || def;
}

Improved syntax given optional chaining

type Header = { headers: Record<string, any> };
type Options = { config : any };

function getHeader(input: Header | Options, key: string, def?: any) {
   return input.headers?.[key] ?? def;
}

Checklist

My suggestion meets these guidelines:

• This wouldn't be a breaking change in existing TypeScript/JavaScript code
• This wouldn't change the runtime behavior of existing JavaScript code
• This could be implemented without emitting different JS based on the types of the expressions
• This isn't a runtime feature (e.g. library functionality, non-ECMAScript syntax with JavaScript output, etc.)
• This feature would agree with the rest of TypeScript's Design Goals.

Thumb up to this issue. Type narrowing is not working with if blocks as well.

declare const foo: { bar: string, method: () => void } | undefined;

if (foo?.bar === 'SUCCESS') {
    foo.method();
}

Playground Link: https://www.typescriptlang.org/play/?ts=3.7-Beta#code/CYUwxgNghgTiAEYD2A7AzgF3gMyUgXPAN7wBGshmMAligOYA08AtiBgBZLCEAUAlPAC8APngA3JNWDwAvvAA+8AK4pQ2WiGABuAFA7q2eD1xIA-ADpyMIYMHwA5AGUAqgGFXAUUeP7AojvhAnDxzVg4ufl0ZIA

[itsMapleLeaf]

Maybe this is also related. I ran into an issue with narrowing discriminated unions:

type Shape =
    | { type: 'rectangle', width: number, height: number }
    | { type: 'circle', radius: number }

declare const shape: Shape | undefined

const radius = shape?.type === 'circle' && shape?.radius

This errors on radius in shape?.radius:

Property 'radius' does not exist on type 'Shape'.
  Property 'radius' does not exist on type '{ type: "rectangle"; width: number; height: number; }'.(2339)

I would expect it know after the && that shape is a circle.

Playground

[Kingwl]

@kingdaro @zhongliangwang
Seems fixed in #33821

[itsMapleLeaf]

Found another similar problem: narrowing doesn't happen properly with switch

type Shape =
    | { type: 'rectangle', width: number, height: number }
    | { type: 'circle', radius: number }

function getArea(shape?: Shape) {
    switch (shape?.type) {
        case 'circle':
            return Math.PI * shape.radius ** 2
        case 'rectangle':
            return shape.width * shape.height
        default:
            return 0
    }
}

Playground

In the latest nightly as of this comment, this does typecheck if I refactor this to if statements

[HoldYourWaffle]

I think I'm encountering a similar issue when using the new assertion statements:

declare function assertNonNull<T>(x: T | null): asserts x is T;
declare const x: { y: T | null } | null;

assertNonNull(x?.y); // Assert y, implicitly assert x
doSomething(x.y); // Error: x is possibly 'null'; the implicit assert for x didn't work

assertNonNull(x); // Explicitly assert x
doSomething(x.y); // No error anymore, both x and y have been narrowed down correctly

I'm using the latest nightly as of 9 october.

[ryanquinn3]

I've stumbled across what appears to be a similar issue to this one.

Heres a link to the playground. Playground is pointing to nightly but for record keeping I'm seeing this on 3.7.0-dev.20191016

The snippet:

type Feature = {
  id: string;
  geometry?: {
    type: string;
    coordinates: number[];
  };
};


function extractCoordinates(f: Feature): number[] {
    if (f.geometry?.type !== 'test') {
        // this case should be hit if f.geometry is undefined 
        return [];
    }
   // doesn't narrow f.geometry to the defined value
    return f.geometry.coordinates;
}

[Kingwl]

@ryanquinn3

// doesn't narrow f.geometry to the defined value
 return f.geometry.coordinates;

That seems expected behavior