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Separately check ternary branches for assignabilityΒ #60813

Closed as not planned
Closed as not planned
@kirkwaiblinger

Description

@kirkwaiblinger

πŸ” Search Terms

ternary, conditional expression, recursion,

βœ… Viability Checklist

⭐ Suggestion

I propose that the following code should error

declare const b: boolean;
declare const a: any;
const s: string = b ? a : 42;

because number is not assignable to string.

This is already the case for the equivalent return statement "assignment", as of #56941.

function foo(b: boolean, a: any): string {
  return b ? a : 42
}

So I think it would make sense to be consistent.

πŸ“ƒ Motivating Example

My real world code looked something like this

declare const x: unknown;
const s: string = x != null ? (x as any).prop : undefined

Another related example, is that this code should be an error

declare const a: any;
const s: string = a ?? 24;

Which relates to #51665 (comment), where an error should/would occur if the RHS of the ?? were checked separately.

πŸ’» Use Cases

  1. What do you want to use this for?
    • Making less errors
  2. What shortcomings exist with current approaches?
    • TS lets me make errors
  3. What workarounds are you using in the meantime?
    • being sad
    • avoiding any as much as possible

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