Unconditionally call checkExpression
from checkSatisfiesExpression
#51704
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An unenforced invariant of our checker is that all subcalls of
checkExpression
must unconditionally callcheckExpression
on their children in order for emit to work.checkSatisfiesExpression
broke this by bailing early when the asserted type was invalid, thus breaking the example shown in the OP and testcasePlayground link showing the problem
Fixes #51642. Propose to port to 4.9.