Wrong parameter name in to_stata() method

[kylebarron]

In the API documentation for df.to_stata(), a parameter dataset_label is listed to give the Stata file a label, however the Pandas API actually uses the parameter data_label.
From core/frame.py:

    def to_stata(self, fname, convert_dates=None, write_index=True,
                encoding="latin-1", byteorder=None, time_stamp=None,
                data_label=None, variable_labels=None):

Thus using dataset_label doesn't work, but data_label does.

>>> import pandas as pd
>>> df = pd.DataFrame({'col1': [1, 2], 'col2': [3, 4]})
>>> df.to_stata('test.dta', dataset_label='data label')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: to_stata() got an unexpected keyword argument 'dataset_label'
>>> df.to_stata('test.dta', data_label='data label')

I'll submit a PR shortly changing that docstring.

Output of pd.show_versions()

INSTALLED VERSIONS

commit: None
python: 3.6.4.final.0
python-bits: 64
OS: Linux
OS-release: 4.13.0-32-generic
machine: x86_64
processor: x86_64
byteorder: little
LC_ALL: None
LANG: en_US.UTF-8
LOCALE: en_US.UTF-8

pandas: 0.22.0
pytest: 3.3.0
pip: 9.0.1
setuptools: 38.5.1
Cython: 0.27.3
numpy: 1.14.0
scipy: 1.0.0
pyarrow: 0.8.0
xarray: None
IPython: 6.2.1
sphinx: 1.6.3
patsy: 0.4.1
dateutil: 2.6.1
pytz: 2017.3
blosc: None
bottleneck: 1.2.1
tables: 3.4.2
numexpr: 2.6.4
feather: 0.4.0
matplotlib: 2.1.1
openpyxl: 2.4.9
xlrd: 1.1.0
xlwt: 1.3.0
xlsxwriter: 1.0.2
lxml: 4.1.1
bs4: 4.6.0
html5lib: 1.0.1
sqlalchemy: 1.1.13
pymysql: None
psycopg2: None
jinja2: 2.10
s3fs: None
fastparquet: None
pandas_gbq: None
pandas_datareader: None

[gfyoung]

Oops? 😄

Good catch!